Question

the sum of the square of 2 consecutive natural number is 313.if one number is x what is the other number
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Answer 1

Step-by-step explanation:

HEY MATE........

Given: sum of the squares of two consecutive natural numbers is 313

To find the numbers

${x}^{2} + ( {x + 1)}^{2} = 313 \\ \\ {x}^{2} + {x}^{2} + 2x + 1 = 313 \\ \\ {2x}^{2} + 2x - 312 = 0 \\ \\ {x}^{2} + x - 156 = 0 \\ \\ (x - 12)(x + 13) = 0 \\ \\ x = 12and \: x = - 13$

Sol: Let 1 number be x. Since the numbers are consecutive, the other number would be x+1.

Square both and add together to equal 313.

given numbers are natural . so x=12 and x+1=13 are the two numbers.