Question

The sum of the square of of two consecutive odd number is 202 find the numbers First number=x

Answer 1

Answer:

x+x=202

2x=202

x=202÷2

x=101

Answer 2

Answer:

Step-by-step explanation:

The numbers are consecutive odd. So let one number be x and other be x+2.

According to the question,

x^2+(x+2)^2 = 202

x^2+x^2+4+4x = 202     ( By using (a+b)^2=a^2+2ab+b^2)

2x^2+4x+4 = 202

2x^2+4x-198 = 0

By simplifying we get,

x^2+2x-99=0

By splitting the middle term we get,

x^+9x-11x-99=0

x(x+9)-11(x+9)

(x-11)(x+9)

So  x=11 or x=-9

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