The sum of the square of the two consecutive natural number is 635 find the number
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let the smaller number be x
x^2+(x+1)^2=635
x^2+x^2+2x+1=635
2x^2+2x=636
2(x^2+x)=636
x^2+x=318
x=318-x^2
x^2+(x+1)^2=635
x^2+x^2+2x+1=635
2x^2+2x=636
2(x^2+x)=636
x^2+x=318
x=318-x^2
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