The sum of the square of three
consecutive
even integers is 200.find the number
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0
Answer:
The sum of the square of three con even integers is 200.So the numbers is 6, 8, 10
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❍ Let the smallest even integers be x, then the other two consecutive even integers are x + 2 and x + 4.
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★ According to given, x² + (x + 2)² + (x + 4)² = 200.
➛ x² + (x² + 4x + 4) + (x² + 8x + 16) = 200
➛ 3x² + 12x + 20 - 200 = 0
➛ 3x² + 12x - 180 = 0
➛ x² + 4x - 60 = 0
➛ (x - 6) (x + 10) = 0
➛ x - 6 = 0 or x + 10 = 0
➛ x = 6 or x = -10
When,
x = 6, x + 2 = 8 and x + 4 = 10;
Then,
x = -10, x + 2 = -8 and x + 4 = -6
✿ Therefore,
Hence, the required integers are 6, 8, 10 or -10, -8, -6.
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