Question

the sum of the square of two consecutive natural no 41 represent this situation in the form of a quartric equation​

Answer 1

Answer:

Let us take the two consecutive natural numbers x and x+1.

So from the equation,

x

2

+(x+1)

2

=41

2x

2

+2x+1−41=0

x

2

+x−20=0

(x+5)(x−4)

x=−5,4

As -5 is not a natural number.

x=4 is the only solution.

Therefore, the two consecutive natural numbers