the sum of the square of two consecutive natural number is 221 .find the number
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Let two consecutive numbers are x & x+1.
a/q,
x^2+(x+1)^2=221
x^2+x^2+1+2x=221
2x^2+2x+1-221=0
2x^2+2x-220=0
x^2+x-110=0
x^2+11x-10x-110=0
x (x+11)-10 (x+11)=0
(x+11)(x-10)=0
either,x=-11 or, x=10
thus, two numbers are 10 and 10+1=11.
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