Math, asked by suresh2510chavan, 4 months ago

The sum of the square of two consecutive odd natural numbers is 299. find the number.

Answers

Answered by Anonymous
6
  • CORRECT QUESTION:-

The sum of the square of two consecutive odd natural numbers is 290.

  • To Find:-

Find the numbers.

  • SOLUTION:-

Let the two odd natural consecutive numbers be x, x + 2.

It is said the sum of their squares is 290.

According to the question,

\large\Longrightarrow{\sf{{(x)}^{2}+{(x+2)}^{2}=290}}

\large\Longrightarrow{\sf{({x)}^{2}+({x}^{2}+4x+4)=290}}

\large\Longrightarrow{\sf{{2x}^{2}+4x+4=290}}

\large\Longrightarrow{\sf{{2x}^{2}+4x+4-290=0}}

\large\Longrightarrow{\sf{{2x}^{2}+4x-186=0}}

Dividing both sides by 2,

\large\Longrightarrow{\sf{{x}^{2}+2x-143=0}}

\large\Longrightarrow{\sf{x(x+13)-11(x+13)=0}}

\large\Longrightarrow{\sf{(x+13)(x-11)=0}}

\large\therefore{\sf{x+13=0}}

\large\therefore{\sf{x-11=0}}

\large\therefore{\sf{x=-13}}

We cannot take negative values.

So,

\large\therefore{\sf{x=11}}

x = 11

x + 2 = 11 + 2 = 13

\large\red\therefore\boxed{\sf{\red{Two \:consecutive\: odd\: natural \:numbers\: are \:11\: and\: 13.}}}

Answered by StylusMrVirus
69

CORRECT QUESTION:-

The sum of the square of two consecutive odd natural numbers is 290.

To Find:-

Find the numbers.

SOLUTION:-

Let the two odd natural consecutive numbers be x, x + 2.

It is said the sum of their squares is 290.

According to the question,

\large\Longrightarrow{\sf{{(x)}^{2}+{(x+2)}^{2}=290}}

\large\Longrightarrow{\sf{({x)}^{2}+({x}^{2}+4x+4)=290}}

\large\Longrightarrow{\sf{{2x}^{2}+4x+4=290}}

\large\Longrightarrow{\sf{{2x}^{2}+4x+4-290=0}}

\large\Longrightarrow{\sf{{2x}^{2}+4x-186=0}}

Dividing both sides by 2,

\large\Longrightarrow{\sf{{x}^{2}+2x-143=0}}

\large\Longrightarrow{\sf{x(x+13)-11(x+13)=0}}

\large\Longrightarrow{\sf{(x+13)(x-11)=0}}

\large\therefore{\sf{x+13=0}}

\large\therefore{\sf{x-11=0}}

\large\therefore{\sf{x=-13}}

We cannot take negative values.

So,

\large\therefore{\sf{x=11}}

x = 11

x + 2 = 11 + 2 = 13

\small\red\therefore\boxed{\sf{\red{Two \:consecutive\: odd\: natural \:numbers\: are \:11\: and\: 13.}}}

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