the sum of the square of two consecutive odd number is 394 find the numbers
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Let the required consecutive odd numbers be x and (x+2) . Then ,
x^2+(x+2)^2=394 .
=>2x^2+4x-390= 0 .
=>x^2+ 2x -195=0
=>x^2+ 15x-13x -195= 0
=> x (x+15)-13 (x+15)=0
=> (x+15) ( x-13)=0.
=>x=-15 or x= 13 .
=>x=13( rejecting x=-15)
Hence, the required numbers are 13 and 15 .
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