Question

the sum of the square of two consecutive odd positive integer is 394 find them.

please help me with this question.
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Answer 1

Let the first positive integer be x

Second consecutive odd positive integer=x+2

Now sum of their squares is equal to 394

x^2+(x+2)^2=394

x^2+x^2+4+4x=394

2x^2+4x+4=394 [÷2]

or x^2+2x+2=197

x^2+2x-195=0

(x-13) (x+15) =0

x=13 coz its a positive integer

So second no. =13+2=15

Check :13^2+15^2=169+225=394

Answer 2

If other answer help you then Ok......