Question

the sum of the squares of 2 consecutive natural numbers is 265. What are the numbers​

Answer 1

let numbers X and second number X+1

acc. to question

x^2 + (x+1)^2 = 256

2x^2+X+1=256

solve it now

Answer 2

Answer:

let two consecutive natural numbers X and X+1

x^2 + (X+1)^2 = 265

x^2 + x^2 + 1^2 + 2x = 265

2x^2 +1 + 2x = 265

x^2 + X - 132 = 0

x^2 + 14x - 13x -132= 0

X(X+14) - 13(x-14) =0

(X+14)(x-13) = 0

X=-14 X=13

X can not be negative

so two consecutive no are 13 and 14