Question

The sum of the squares of 2 numbers is 146 and the square root of one of them is root5. The cube of the other number is

Answer 1

$\huge{\textsf{\red{solution}}}$

Let two numbers are x & y. 

x2+y2=146x2+y2=146

25+y2=14625+y2=146

y2=146−25y2=146−25

y2=121y2=121

y = 11

Therfore, y3=(11)3=1331

$\huge{\textsf{\green{hope \: it \: help \: you}}}$

Answer 2

the answer is 1331......