Question

the sum of the squares of 3 conscecutive numbers positive number is 365 .Accordingly what is the sum of those number?​

Answer 1

Answer:

Let the numbers be x, x+1, x+2

ATQ

Let the 3 consecutive positive numbers = x, x +1, x + 2

According to the question,

=> x2+(x+1)2+(x+2)2=365

=> x2+x2+1+2x+x2+4+4x=365

=> 3x2+6x−360=0

=> x2+2x−12=0

=> x×(x+2)=120

=> x(x+2)=10×12=120

=> x = 10

Therefore, Sum of the numbers = 10 + 11 + 12 = 33