the sum of the squares of five consecutive terms natural numbers is 1445 find them
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287, 288,289,290,291
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Answer;
The five consecutive natural numbers are= 287,288,289,290,291
Step-by-step explanation:
x+(x+1)+(x+2)+(x+3)+(x+4)=1445
Now, x+x+x+x+x+1+2+3+4=1445
5x+10=1445
5x=1445-10
5x=1435
x=1435/5
X=287
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