The sum of the squares of its distances from A(3, 0) and B(-3, 0) is four times the distance from A and B.
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Answer:
x²+y²-63= 0
Step-by-step explanation:
Let P(x, y) be the point
Given PA²+PB²= 4AB
(x-3)²+(y)²+(x+3)²+(y)² = 4[(3+3)²]
x²-6x+9+y²+x²+6x+9+y²= 4(36)
2x²+2y²+18= 144
2x²+2y²= 144-18
2(x²+y²) = 126
x²+y²= 63
x²+y²-63=0
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