the sum of the squares of the two positive integers is 117 the square of the smaller number equals four times the larger number we need to find the integers
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HEY !!!!
SEE THE ATTACHED FILE.
THEN PUT THE VALUE OF X IN Y FORM
YOU WILL GOT IT. x^2 + y^2 = 117 x^2 = 4y ============ y^2 + 4y - 117 = 0 y = 9 x = 6
SEE THE ATTACHED FILE.
THEN PUT THE VALUE OF X IN Y FORM
YOU WILL GOT IT. x^2 + y^2 = 117 x^2 = 4y ============ y^2 + 4y - 117 = 0 y = 9 x = 6
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