Question

the sum of the squares of three consecutive natural numbers is 194.the numbers are options are (a)5,6,7 ,(b)7,8,9 ,(c)4,5,6 and (d)6,7,8

Answer 1

Answer:

Step-by-step explanation:

x²+(x+1)²+(x+2)²=194

3x²+6x+5=194

3x²+6x-189=0

3x²+27x-21x-189=0

3x(x+9)-21(x+9)=0

(3x-21)(x+9)=0

Therefore

x=21/3=7 or

x=-9

Taking x as 7, the numbers are 7,8,9.

So option B is your answer.

Hope this helps you.

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Answer 2

Answer:let the no be :x

                                    x+1

                               and x+2

therefore, according to the question

(x*x )+(x*x + 1+ 2x)+(x*x +4 + 4x)=194

3(x*x) +6x + 5 =194

3(x*x) + 6x - 189 = 0

therefore,  x = -9 and x = 7

therefore,

      x = 7

the three consecutive natural no are

7 , 7+1 , 7+2

7 , 8 , 9

Step-by-step explanation: