Question

the sum of the squares of three consecutive odd number is 38,find the number. fofor 3marks

Answer 1

(x)2 +(x+2)2+ (x+4)2=38
apply this u will get ur answer

Answer 2

Let three consecutive odd no's are x,x+2,x+4... According to Q's: x^2+(x+2)^2+(x+4)^2=38 => x^2+x^2+2x+4+x^2+8x+16= 38 => 3x^2+10x+20-38=0 => 3x^2+10x-18= 0 now if we further solve it not getting real roots of equation means no such numbers are there whose sum of squares is 38