Question

the sum of the squares of three numbers is 116 and their ratio is 2 ratio 3 ratio 4ratio. the numbers are

Answer 1

Let the numbers be 2x, 3x and 4x


According to question

(2x)^2 + (3x)^2 + (4x)^2 = 116
=> 4x^2 + 9x^2 + 16x^2 = 116
=> 29x^2 = 116
=> x^2 = 4

x= 2


First no. = 4
Second no. = 6
Third no. = 8

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