The sum of the squares of three numbers is 532 and the ratio of the first to the second as also of the second to the third is 3:2. what is the second number?
Answers
Answered by
9
A/B=3/2 and B/C=3/2..
THAN A=(3/2)*B and C=(2/3)*B
NOW A/C TO QUES
A^2+B^2+C^2=532
putting the values we get
(9/4)* B^2 + B^2 + (2/3)* B^2 = 532
solving this you will get B^2=144
so B=12
put its valus at place of A and C
u will get A=18, B=12 ,C=8... your required answer is 12
THAN A=(3/2)*B and C=(2/3)*B
NOW A/C TO QUES
A^2+B^2+C^2=532
putting the values we get
(9/4)* B^2 + B^2 + (2/3)* B^2 = 532
solving this you will get B^2=144
so B=12
put its valus at place of A and C
u will get A=18, B=12 ,C=8... your required answer is 12
Answered by
4
Answer:
Ratio of three numbers = a*a a*b b*b
take a=3 b=2
therefore 9,6,4 take as X,Y,Z
( (X)^2 + (Y)^2 + (Z)^2) )k^2 = 532
( (9)^2 + (6)^2 + (4)^2) )k^2 = 532
( 81 + 36 + 16)k^2 = 532
133^2 = 532
we get k = 2
if we multiply 2 with ratios we will get the answer
the numbers are
X= 9*2=18
Y= 6*2=12
Z= 4*2=8
Step-by-step explanation:
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