The sum of the squares of three numbers which are in ratio 3:4:5 is 800. What are the numbers?
Answers
Answered by
9
let the common ratio be x
it is given that (3x)^2+(4x)^2+(5x)^2=800
50x^2= 800
x^2 = 16
x=4
no.s are 12,16 and 20
it is given that (3x)^2+(4x)^2+(5x)^2=800
50x^2= 800
x^2 = 16
x=4
no.s are 12,16 and 20
brofist0072:
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Answered by
12
hello users ...
solution:-
Given that:
Three numbers are are in ratio
3 : 4 : 5
And
sum of square of these three numbers = 800
Now,
let,
first number be = 3x
second number = 4x
And
third number = 5x
According to given :
(3x)² + (4x)² + (5x)² = 800
=> 9x² + 16x² + 25x² = 800
Taking x² common ....
=> (9 + 16 + 25) x² = 800
=> 50x² = 800
=> x² = 800/50 = 16
=> x = 4
Hence ;
first number = 3x = 3*4 = 12
second number= 4x = 4*4 = 16
And
third number = 5x = 5*4 = 20 Answer
# hope it helps :)
solution:-
Given that:
Three numbers are are in ratio
3 : 4 : 5
And
sum of square of these three numbers = 800
Now,
let,
first number be = 3x
second number = 4x
And
third number = 5x
According to given :
(3x)² + (4x)² + (5x)² = 800
=> 9x² + 16x² + 25x² = 800
Taking x² common ....
=> (9 + 16 + 25) x² = 800
=> 50x² = 800
=> x² = 800/50 = 16
=> x = 4
Hence ;
first number = 3x = 3*4 = 12
second number= 4x = 4*4 = 16
And
third number = 5x = 5*4 = 20 Answer
# hope it helps :)
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