The sum of the squares of two consecutive even integers is 1252. Find the integers.
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Let the two consecutive integers be x and x+1
X^2 +(x+1)^2 =1252
2x^2+1 + 2x=1252
2x^2 -1251+ 2x=0
Then solve the remaining question by factorisation method
X^2 +(x+1)^2 =1252
2x^2+1 + 2x=1252
2x^2 -1251+ 2x=0
Then solve the remaining question by factorisation method
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