Math, asked by chhavi5418, 1 year ago

The sum of the squares of two consecutive integers is 41

Answers

Answered by nayan6227
2

Answer:

20,21

Step-by-step explanation:

Sum of consecutive integers is

x, x+1

so

x+x+1=41

2x=41-40

x=21

Consecutive integers

are 20 and 20+1

Answer=20&21

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Answered by mysticd
6

Answer:

Required consecutive integers are (-5,-4), Or (4,5)

Step-by-step explanation:

Let x , (x+1) are two consecutive Integers.

According to the problem given, we get

+(x+1)² = 41

=> ++2x+1-41=0

=> 2x²+2x-40=0

Divide each term by 2 ,we get

=> +x-20=0

=> +5x-4x-20=0

=> x(x+5)-4(x+5)=0

=> (x+5)(x-4)=0

=> x+5 = 0 Or x-4 = 0

=> x = -5 Or x = 4

Therefore,

Required two consecutive Integers are x,(x+1)

i) If x = -5,

Required integers -5,-4

ii) If x = 4,

, Required integers 4,5

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