The sum of the squares of two consecutive integers is 41
Answers
Answered by
2
Answer:
20,21
Step-by-step explanation:
Sum of consecutive integers is
x, x+1
so
x+x+1=41
2x=41-40
x=21
Consecutive integers
are 20 and 20+1
Answer=20&21
Mark as brainliest
Answered by
6
Answer:
Required consecutive integers are (-5,-4), Or (4,5)
Step-by-step explanation:
Let x , (x+1) are two consecutive Integers.
According to the problem given, we get
x²+(x+1)² = 41
=> x²+x²+2x+1-41=0
=> 2x²+2x-40=0
Divide each term by 2 ,we get
=> x²+x-20=0
=> x²+5x-4x-20=0
=> x(x+5)-4(x+5)=0
=> (x+5)(x-4)=0
=> x+5 = 0 Or x-4 = 0
=> x = -5 Or x = 4
Therefore,
Required two consecutive Integers are x,(x+1)
i) If x = -5,
Required integers -5,-4
ii) If x = 4,
, Required integers 4,5
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