Question

the sum of the squares of two consecutive numbers is 221 find the numbers

Answer 1

Hlo Friend
Let x and x+1 be the consecutive integers. 

The sum of squares is: 
(x)² + (x+1)² = 221 
Expand second term: 
x² + x² + 2x + 1 = 221 
Combine like terms: 
2x² + 2x + 1 = 221 
Subtract 221 from both sides to make quadratic form: 
2x² + 2x - 220 = 0 
Divide both sides by 2: 
x² + x - 110 = 0 
Factor: 
(x + 11)(x - 10) = 0 
x = -11 or x = 10 

Answers: 10 and 11 or -10 and -11 

Answer 2

hope it helps you ans 10 and 11