the sum of the squares of two consecutive odd natural numbers is 290 . find the Numbers
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Answered by
7
(2n+1)^2+(2n+3)^2=290
4n^2+4n+1+4n^2+12n+9=290
8n^2+16n+10=290
8n^2+16n-280=0
n^2+2n-35=0
(n+7)(n-5)=0
n=-7 which is not possible because no can't be negative
n=5
2n+1=2*5+1=11
2n+3=13
11^2+13^2=121+169=290
4n^2+4n+1+4n^2+12n+9=290
8n^2+16n+10=290
8n^2+16n-280=0
n^2+2n-35=0
(n+7)(n-5)=0
n=-7 which is not possible because no can't be negative
n=5
2n+1=2*5+1=11
2n+3=13
11^2+13^2=121+169=290
Answered by
8
Let the two consecutive odd natural numbers be x+1 and x+3.
According to the given condition,we get,
x^2+4x-140=0
Solve it u will get two numbers -14 or 10
So , in que it is told that two consecutive odd natural numbers .
Therefore , the numbers are
x+1=10+1=11
x+3=10+3=13
Therefore , the numbers are 11 and 13.
HOPE U LIKED IT ……
According to the given condition,we get,
x^2+4x-140=0
Solve it u will get two numbers -14 or 10
So , in que it is told that two consecutive odd natural numbers .
Therefore , the numbers are
x+1=10+1=11
x+3=10+3=13
Therefore , the numbers are 11 and 13.
HOPE U LIKED IT ……
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