The sum of the squares of two consecutive odd natural numbers is 290 , find the numbers ?
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Answer:
The integers are 11, 13.
Step-by-step explanation:
Let the first integer be x. Then the second integer is x + 2.
Given that sum of squares of two consecutive integers is 290.
x^2 + (x+2)^2 = 290
x^2 + x^2 + 4x + 4 = 290
2x^2 + 4x + 4 = 290
2x^2 + 4x = 286
x^2 + 2x = 143
x^2 + 2x - 143 = 0
x^2 + 13x - 11x - 143 = 0
x(x + 13) - 11(x + 13) = 0
(x + 13)(x - 11) = 0
x = 11,-13.
If x = 11 then x + 2 = 13.
The integers are 11, 13.
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