Question

The sum of the squares of two consecutive odd nos is 394.Find the nos​

Answer 1

Answer:

Step-by-step explanation:

let the number be n

the next odd number would be n+2(as n+1 would be even)

n^2+(n+2)^2 = 394

n^2+n^2+4n+4=394

2n^2+4n=390

n^2+2n=195 (after dividing by 2 on both sides)

n^2+2n-195=0

n^2+15n-13n-195=0

n(n+15)-13(n+15)=0

n=13,(-15)

but if n= -15,

(-15)^2 + (-17)^2=514

thus,

n=13