Question

the sum of the squares of two consecutive odd numbers is 394.find the numbers​

Answer 1

Answer:

numbers are 13 , 15

Step-by-step explanation:

Let the first number be n, then the next consecutive odd number is n+2

Squares of two consecutive odd numbers is 394

=> n² + (n+2)² = 394

=> n² + n²+ 4n + 4 = 394

=> 2n² + 4n - 390 = 0

=> n² + 2n - 195 = 0

=> n² + 15n - 13n - 195 = 0

=> n(n+15) - 13(n+15) = 0

=> (n-13)(n+15) = 0

=> n = 13 or -15

Since n cannot be negative, the numbers are 13 , 15

Answer 2

Answer:

15

Step-by-step explanation:

${x}^{2} + ({x + 2} )^{2} = 394$

${x}^{2} + 2x - 195$

$(x - 13)(x + 15) \\ x = 13$

x=15