The sum of the squares of two consecutive odd numbers is 394. The mathematica equation for the above statement is A. x2+(x+1)=394 B. x2+(x+2) =394 C. (x+1)+ (x+2)2 =394 D. x+(x+2)2=394
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Answered by
2
Step-by-step explanation:
let the number are x and x+2
ATQ x^2+(x+2)^2=394
Answered by
2
Step-by-step explanation:
Let two consecutive odd number be x and x+2
According to the question,
⇒ x
2
+(x+2)
2
=394
⇒ x
2
+x
2
+4x+4=394
⇒ 2x
2
+4x−390=0
⇒ x
2
+2x−195=0
⇒ x
2
+15x−13x−195=0
⇒ x(x+15)−13(x+15)=0
⇒ (x+15)(x−13)=0
⇒ x+15=0 and x−13=0
⇒ x=−15 and x=13
∴ On number is 13
⇒ Other number =13+2=15
⇒ Required product =13×15=195
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