Question

The sum of the squares of two consecutive odd positive integers is 394. find the integers 10th class

Answer 1

let fisrt no. be =x
there another number be=x+1
a.t.q
x²+(x+1)²=394
x²+x²+1²+2(x*1)= 394
x²+x²+1+2x=394
2x²+2x=394-1
2x²+2x=393
2x²+2x=393
2x²+2x-393=0

then after solvving this equation u get answer

Answer 2

Method of solution;-

let to be first consecutive odd positive(2x+1) and second consecutive odd positive(2x+3)

According to the question;-

(2x+1)+(2x+3)²=394

4x²+1+4x+4x²+9+12x=394

8x²+16x-384=0

8(x2+2x-48)=0

x²+8x-6x-48=0

x(x+8)-6(x+8)=0

(x+8)(x-6)=0

x=-8 x=6

x1=2(6)+1=13

x2=2(6)+3=15

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Hence, Numbers are 13 and 15.