Question

The sum of the squares of two consecutive odd positive integers is 202 write the quadratic equation

Answer 1

Since they are consecutive odd integers, then we can just divide 202 by 2, square root it, then round to the nearest two odd integers.

In this case, 202 / 2 = 101 ⇒ 1010.5 ≈ 10.04. The two nearest odd integers are 9 and 11. We can verify that this is the pair: 92 + 112 = 81 + 121 = 202.

Answer 2

Step-by-step explanation:

Let the numbers be X and X + 2

According to the question,

(x)² + (x+2)² = 202

x² + x² + 4 + 4x = 202

2x² + 4x - 198 = 0

2 ( x² + 2x - 99 ) = 0

x² + 2x - 99 = 0

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