the sum of the squares of two consecutive positive integer is 365 .find the number.
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13. &. 14 are the positive 2consecutive integers whose sum is 365...
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let the two consecutive positive integers be x,x+1
(x)^2+(x+1)^2=365
x^2+x^2+2x+1=365
2x^2+2x=364
2x^2+2x-364 =0
2x^2+28x-26x-364=0
2x(x+14)-26(x+14)=0
(x+14) -(2x-26)=0
x=-14 , x=13
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