Question

The sum of the squares of two natural number is 29. If the second number is one more than twice the first number find the numbers

Answer 1

Substituting the value of x in (1) (2y - 1)2 + y2 = 34 4y2 - 4y + 1 + y2 = 34 5y2 - 4y - 33 = 0 (5y + 11)(y - 3) = 0 y = -11/3, 3 Among both the numbers, 3 is the natural number. Therefore, one of the numbers is 3 and the other number is 2(3) - 1 i.e. 5.