Question

The sum of the squares of two natural numbers is 116 if the square of the larger number is 25 times the smaller number , find the numbers

Answer 1

10 and 4 are required answer

Answer 2

Answer:

Step-by-step explanation:

Let be the 1st natural no.=x

Let be the 2nd natural no.=y

X ka square + y ka square =116 equation no.1

X is grater than y

X ka square =25y ka square equation no.2

Put equation 2 in 1

yka square +25y -116

y ka square +29y-4y-116=0

y(y+29)-4(y+29)

(y-4)(y+29)

y-4=0

y=4

y+29=0

y=-29

Nagetive value is rejacted

y=4 put in equation no.2

x=10

Therefore 1st no. is 4

2nd no. is 10