The sum of the squares of two natural
numbers is 29. If the second number is one
more than twice the first number, find the
numbers.
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Let the two no.s be x and y.
A.T.Q,
x + y = 29
and y = 2x + 1
therefore,
x + 2x + 1 = 29
3x = 28
x =28/3
and y =2x + 1
y = 56/3 + 1
y = 59/3
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