Question

the sum of the squares of two number is 3341 and the difference of their squares is 891 the two number are​

Answer 1

Answer:

Bro , the no. are = 46 and 35

Step-by-step explanation:

full explaination is in the image

hope you like the answer

Answer 2

Given: sum of the squares of two number = 3341   and the difference of their squares is 891

To find: the two numbers

Step-by-step explanation:

According to question

Let the number be x and y

$x^2+y^2=3341-(i)$

$x^2-y^2=891-(ii)$

By using elimination method

$2x^2=4232$

$x^2=\frac{4232}{2}$

$x^2=2116$

$x=\sqrt{2116}$

$x=46$

Put $x=46$ in equation (i) to find the value of y

$x^2+y^2=3341$

${46}^2+y^2=3341$

$2116+y^2=3341$

$y^2=3341-2116$

$y^2=1225$

$y=\sqrt{1225}$

$y=35$

Hence, the two numbers are 46 and 35