Question

The sum of the squares of two numbers is 1088. If one of the numbers is 8, find the other number.​

Answer 1

Answer:

let the other number be x

(8)^2 + x^2 =1088

64+x^2=1088

x^2= 1088-64

x^2 = 1024

x= 32

therefore the other number = 32