Question

the sum of the squares of two numbers is 233 and one of the number is 3 less than twice the other number. find the number​

Answer 1

Answer:

8 , 13

Step-by-step explanation:

⇒  Let the number be x

⇒  Then the other number =2x−3

According to the question,

⇒  x2+(2x−3)2=233

⇒  x2+4x62+9−12x=233

⇒  5x2−12x−224=0         ------ ( 1 )

⇒  Here, a=5,b=−12,c=−224

⇒  x=2a−b±b2−4ac

          =2(5)−(−12)±(−12)2−4(5)(−224)

          =1012±144+4480

          =1012±4624

          =1012±68

⇒  1012+68  and x=10