Question

the sum of the squares of two numbers is 233. one of the number is 3 less than twice the other number.fine the 2 numbers.

Answer 1

Let the numbers be x and y 

x+y=233?(1) 

2y-x=3 

x=2y-3? (2) 

put in 1st eqn 

(2y-3)+y=233 

4y+9-12y+y=233 

5y-12y-224= 0 

5y-40y+28y-224=0 

(y-8)(5y+28)= 0 

y=8,-28/5 

put in 2nd 

x= 13

Answer 2

Answer:

Step-by-step explanation:

Let one number ne x

Other number is then= 2x-3

So (2x-3)^2 +(x)^2=223

On solving quadratic We get x = 8,-25/8

8 would be accepted as other is not a

Natural number

Henderson no's are=8,13