Question

The sum of the squares of two numbers is 394, and the difference of their squares is 56. What are the numbers?

Answer 1

The number are 13 and 25

Answer 2

let the two numbers be 'a' and 'b'

given, a^2+b^2 =394 -----(1)

and a^2-b^2=56------(2)

by adding (1) and (2) we get

2a^2=450

a^2=225

a=+15 or -15

by subrating (1) -(2)

2b^2=338

b^2=169

b=+13or -13

I hope this will help u :)