Question

The sum of the squares of two numbers is 41. The difference of the squares of these numbers is 9 What are the numbers?

*PLEASE HELP FAST*​

Answer 1

Answer:

Let the numbers be x and y

then, x²+y² = 41

and x²-y² = 9

by adding two equations 2x² = 50

=> x²= 25

=> x= 5

then substituting x in equation

we get, y = 4.

Thanks.

Like Follow and Rate.

Teacher.

Answer 2

Step-by-step explanation:

Given that

x+y=9

Squaring both sides, we get

x

2

+y

2

+2xy=81

Also given that

x

2

+y

2

=41

⇒2xy=40;xy=20

⇒y=

x

20

Substituting this in 1st equation, we get

x+

x

20

=9

This gives,

x

2

−9x+20=0

This is a quadratic equation, solving this we get

x=

2

9±

9

2

−4×20

=4,5

∴ Numbers are 4 and 5