Question

The sum of the squares of two positive integers is 117. If the square of the smaller number
equals four times the larger number, find the integers.

Answer 1

Answer:

Let x be one integer and y be another.

therefore x2=4y

Now,

x2+y2=117

x2=117-y2

117-y2=4y(sincex2=4y)

y2+4y-117=0

y2+13y-9y-117=0

y(y+13)-9(y+13)=0

y=9 or y=-13

since y cannot be negative y=9

integers are y=9

and x2/4=9

or x2=9*4

or x= root 36

or x=6

hope you got it!!!

PLEASE MARK ME AS BRAINLIST ANSWERS PLEASE PLEASE REQUESTING

Answer 2

$\huge{\fbox{\fbox{\bigstar{\mathfrak{\red{Answer}}}}}}$