Question

The sum of the successor and the predecessor of a number is 1326. The number is
(a) 663
(b) 662
(c) 664
(d) 661
[Hint: Let the required number be x. Then, (x + 1) + (x - 1) = 1326. Find x.]
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Answer 1

Step-by-step explanation:

$x + 1 + x - 1 = 1326 \\ 2x = 1326 \\ x = 1326 \div 2 = 663$

Answer 2

Answer:

The answer is 663

Step-by-step explanation:

Hope it helps