Math, asked by ritusingh50522, 5 hours ago

The sum of the successor and the predecessor of a number is 1326 what's the number

Answers

Answered by pranilyankanchi
1

Answer:

Step-by-step explanation:

\begin{gathered}x + 1 + x - 1 = 1326 \\ 2x = 1326 \\ x = 1326 \div 2 = 663\end{gathered}

x+1+x−1=1326

2x=1326

x=1326÷2=663

Answered by panditmurlidhar1982
5

Step-by-step explanation:

let the number be x

then

successor=x+1

predecessor=x-1

ATQ

(x+1)+(x-1)=1326

x+1+x-1=1326

2x=1326

x=1326/2

x=663

hence the required no. is 663

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