Question

the sum of the successors of two numbers is 44 and the difference of their predecessors is 18 frame a equation in two variables for this

Answer 1

here is your answer by Sujeet

let to be first no be x
"""""""""""""""" second no be y

A/q
x+y=44
x-y=18



now solving the equation,
by elimination method
x+y=44
x-y=18
----------
2y=26
y=26/2
y=13

now ,
x+y=44
x+13=44
x=44-13
x=31

that's all Sujeet