Question

the sum of the terms(1+2) +(1+2+2 square )+( 1+2+2 square +2 cube)+......+n terms is

Answer 1

Step-by-step explanation:

b=c

multiply lhs by 0

multiply rhs by 0

lhs multiplied by 0=0

rhs multiplied by 0=0

lhs=0

rhs=0

0=0

lhs= rhs

hence proved