The sum of the third and seventh term of an arithmetic progression is 300. What is the value of the 5th term of the progression?
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Answer:
150
Step-by-step explanation:
tn = a + ( n - 1 ) d
t3 = a + 2d
t7 = a + 6d
According to the condition ,
a + 2d + a + 6d = 300
2a + 8d = 300
a + 4d = 150 ....... Dividing by 2 .... ( 1 )
tn = a + ( n - 1 ) d
t5 = a + 4d
From ( 1 ) ,
t5 = 150
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