Math, asked by adityavarma046, 9 months ago

The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of the first sixteen terms of the AP.

Answers

Answered by teicandy09
2

Answer:

a+2d+a+6d=6—1

(a+2d)(a+6d)=8—2

2a+8d=6

a^2+12d^2+8ad=8

2a=6-8d

a=6-8d/2

(6-8d/2)^2+12d^2+8(6-8d/2)d=8

36-64d/4+12d^2+(48-64d/16)d=8

144-256d+72d^2+48d-64d^2=128

144-208d+8d^2=128

8d^2-208d+144-128=0

d^2-26d+2=0

d=26

2a+8(26)=6

2a+208=6

2a=6-208

2a=-202

a=-101

For the 16th term

a+15d

-101+15(26)

=289

Step-by-step explanation:

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