Question

The sum of the three consecutive multiples of 7 is 63. Find these mulitiples

Answer 1

Let three consecutive multiples of 7 be 7x,7x+7 and 7x+14

Sum of three consecutive multiples of 7 = 63

7x+7x+7+7x+14 = 63

21x+21 = 63

21(x+1) = 63

(x+1) = 63/21

x+1 = 3

x = 2

therefore,

The multiples are 7(2) = 14

7x+7 = 14+7 = 21

7x+14 = 14+14 = 28

Answer 2

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