Question

the sum of the three consecutive multiples of 8 is 888 find the multiples

Answer 1

8(x-1)+8x+8(x+1)=888 correct answer

Answer 2

let the multiples be 8x ,8(x+1), 8(x+2)
Now,
8x+8(x+1)+8(x+2)=888
x+x+1+x+2=111
3x=111-3
3x=108
x=36
Now multiples=
8x=36×8=288
8(x+1)=296
8(x+2)=300