Question

The sum of the three consecutive odd numbers is 63 . find them

Answer 1

Let the consecutive odd numbers be
$x$
$x + 2$
and
$x + 4$
if we add them, we get,
$x + x + 2 + x + 4 = 3 \times x + 6$
Given that,
$3x + 6 = 63$
So,
$x + 2 = 21$
Therefore,
$x = 19$
So we get the number as x=19, x+2 = 21 and x+4 = 23

Answer 2

Here is your solution

Let,
The first odd integer be:x

Then the second odd integer is:-
x+2

Then the third odd integer is:-
x+2+2=x+4

Sum of three consecutive odd numbers =63

A/q

(x)+(x+2)+(x+4)=63
3x+6=63
3x=63-6
3x=57
x=19
now

The first integer is: x=19

the second integer is: x+2=19+2 = 21

the third integer is: x+4=19+4=23

Hope it helps you